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Cone-Bottom Tank volume formula

Total volume, exact partial fill, derivation, worked example and a copy-ready fill table.

Total volume
V = πr²Hcone/3 + πr²Hcyl
Partial fill at liquid depth h
h≤Hcone: V = π(r·h/Hcone)²·h/3 | h>Hcone: V = Vcone + πr²(h−Hcone)seg(r,h) = r²·acos((r−h)/r) − (r−h)·√(2rh−h²). All closed-form — spreadsheet-implementable with ACOS and SQRT.

Derivation

Inside the cone the wetted radius grows linearly with depth, so volume grows with the cube of depth — which is why the bottom of a cone tank holds almost nothing. Above the knuckle it switches to plain cylinder math. At 40% depth this representative tank holds only 25.9% of its volume.

Worked example

Take D = 48 in, Hcyl = 60 in, Hcone = 24 in. Total capacity: 532.7 gal. At a stick reading of 33.6 in (40% of the 84 in maximum depth), the filled volume is 137.9 gal — 25.9% of capacity. Check it live on the calculator.

Fill ratio: % of depth → % of volume (cone height = D/2, shell = 1.25×D)
DepthVolume
5%0.1%
10%0.5%
15%1.7%
20%4%
25%7.9%
30%13.5%
35%19.7%
40%25.9%
45%32.1%
50%38.2%
55%44.4%
60%50.6%
65%56.8%
70%62.9%
75%69.1%
80%75.3%
85%81.5%
90%87.6%
95%93.8%

Need the full inch-by-inch table for specific dimensions? The dip chart generator prints it as a laminate-ready PDF.

FAQ

What is the formula for a cone-bottom tank volume?

Total: V = πr²Hcone/3 + πr²Hcyl. Partial fill at depth h: h≤Hcone: V = π(r·h/Hcone)²·h/3 | h>Hcone: V = Vcone + πr²(h−Hcone). Derivation and a worked example are above.

Is the fill-ratio table exact?

Yes — computed by the same engine as our calculators (cone height = D/2, shell = 1.25×D), verified by the automated test suite described on the methodology page.

Can I use this in a spreadsheet?

Yes — the formulas are closed-form (acos and sqrt only). Copy the 5%-step table for quick interpolation, or implement the formula directly for exact values.