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Formula · Vertical Tank, 2:1 Dished Bottom

Vertical Tank, 2:1 Dished Bottom volume formula

Total volume, exact partial fill, derivation, worked example and a copy-ready fill table.

Total volume
V = (2/3)πr²a + πr²Hcyl, a = D/4
Partial fill at liquid depth h
h≤a: V = (r/a)²·πh²(3a−h)/3 | h>a: V = (2/3)πr²a + πr²(h−a)seg(r,h) = r²·acos((r−h)/r) − (r−h)·√(2rh−h²). All closed-form — spreadsheet-implementable with ACOS and SQRT.

Derivation

The bottom head is half a spheroid standing on its pole. Stretch a sphere of radius a horizontally by r/a: areas scale by (r/a)², so the head's partial fill is exactly (r/a)² times a spherical cap of radius a. Above the tangent line, linear cylinder math takes over.

Worked example

Take D = 48 in, Hcyl = 60 in. Total capacity: 532.7 gal. At a stick reading of 28.8 in (40% of the 72 in maximum depth), the filled volume is 194.3 gal — 36.5% of capacity. Check it live on the calculator.

Fill ratio: % of depth → % of volume (2:1 head (depth D/4), shell = 1.25×D)
DepthVolume
5%1.4%
10%5.1%
15%10%
20%15.3%
25%20.6%
30%25.9%
35%31.2%
40%36.5%
45%41.8%
50%47.1%
55%52.4%
60%57.6%
65%62.9%
70%68.2%
75%73.5%
80%78.8%
85%84.1%
90%89.4%
95%94.7%

Need the full inch-by-inch table for specific dimensions? The dip chart generator prints it as a laminate-ready PDF.

FAQ

What is the formula for a vertical tank, 2:1 dished bottom volume?

Total: V = (2/3)πr²a + πr²Hcyl, a = D/4. Partial fill at depth h: h≤a: V = (r/a)²·πh²(3a−h)/3 | h>a: V = (2/3)πr²a + πr²(h−a). Derivation and a worked example are above.

Is the fill-ratio table exact?

Yes — computed by the same engine as our calculators (2:1 head (depth D/4), shell = 1.25×D), verified by the automated test suite described on the methodology page.

Can I use this in a spreadsheet?

Yes — the formulas are closed-form (acos and sqrt only). Copy the 5%-step table for quick interpolation, or implement the formula directly for exact values.